QCC Notes
CLASS 11 · CHEMISTRY JEE MAIN × NEET हिंदी
§ 1.7NCERT Class 11 · Chemistry · Chapter 1

Atomic and Molecular Masses: Formulas & Numericals

How chemists weigh the unweighable — the carbon-12 scale, chlorine’s famous 35.5, molecular versus formula mass, and the algebra of isotope abundances, with a live lab to run the numbers yourself.

01

What are Atomic and Molecular Masses? — Complete Theory

A single hydrogen atom weighs about 0.000 000 000 000 000 000 000 001 67 g — a number no balance displays and no exam expects you to carry. Chemistry’s fix is elegant: stop weighing atoms in grams, start comparing them to a standard atom. Since 1961 that standard is carbon-12. One ¹²C atom is assigned exactly 12 units, everything else is measured against it, and the unit is the unified mass unit (u): 1 u = 1/12 the mass of one ¹²C atom = 1.6605 × 10⁻²⁴ g. (History in one line: hydrogen’s scale → oxygen’s scale → ¹²C, chosen because it gave the cleanest, most reproducible mass-spectrometry reference.)

So atomic mass is a ratio, not a weight. Saying “oxygen’s atomic mass is 16 u” means one oxygen atom is sixteen times heavier than 1/12 of a carbon-12 atom — and, usefully, sixteen times heavier than a hydrogen atom. Because it is a ratio, the atomic-mass table carries no grams anywhere; grams enter only when you convert through 1 u or through the mole.

Average atomic massx̄ = Σ fᵢ·mᵢ Molecular massM = Σ nᵢ·aᵢ One entitym = M / NA

But why do atomic masses land on awkward decimals — chlorine at 35.5, never a whole number? Because natural samples are isotope mixtures. Chlorine occurs as Cl-35 (≈75%) and Cl-37 (≈25%), and every bottle of chlorine on Earth carries the same blend. The atomic mass is therefore a weighted average: x̄ = (0.75 × 35) + (0.25 × 37) = 35.5 u. Neon mixes three isotopes (20, 21, 22) and averages 20.18 u. The fraction fᵢ is the abundance as a fraction — the sum of all fᵢ must be 1, and that check is free marks.

Table 1 — Atomic masses to memorise (exam convention)
ElementSymbolAtomic mass (u)Exam note
HydrogenH1True value 1.008 — papers use 1
CarbonC12The scale’s anchor (¹²C = 12 exactly)
NitrogenN14—
OxygenO16—
SodiumNa23—
SulfurS32—
ChlorineCl35.5Isotope average — 75% Cl-35 : 25% Cl-37
PotassiumK39—
CalciumCa40—
IronFe56—
CopperCu63.5Isotope average (63 : 65 mix)
SilverAg108—

Step up from atoms to compounds and the same arithmetic adds instead of averages. The molecular mass of a covalent molecule is the sum of atomic masses over its atoms: water = 2(1) + 16 = 18 u, glucose = 6(12) + 12(1) + 6(16) = 180 u, ammonia = 14 + 3(1) = 17 u. For ionic compounds there are no molecules — a crystal of NaCl is a lattice of ions, so we speak of formula mass: one formula unit NaCl = 23 + 35.5 = 58.5 u, CaCO3 = 40 + 12 + 3(16) = 100 u, MgCl2 = 24 + 2(35.5) = 95 u.

Table 2 — Molecular and formula masses, worked
SpeciesTypeWorkingResult
H2OMolecular2(1) + 1618 u
NH3Molecular14 + 3(1)17 u
CO2Molecular12 + 2(16)44 u
C6H12O6Molecular6(12) + 12(1) + 6(16)180 u
NaClFormula23 + 35.558.5 u
CaCO3Formula40 + 12 + 3(16)100 u
MgCl2Formula24 + 2(35.5)95 u

Now the bridge that makes this whole section pay off: the molar mass of a substance in g/mol is numerically equal to its atomic or molecular mass in u — 18 u ↔ 18 g/mol. That single equality is what makes 1 u = 1/NA g = 1.6605 × 10⁻²⁴ g, and it lets you weigh out a countable army of molecules on a kitchen-scale instrument. Need one entity instead of a mole? Divide: mass of one atom or molecule = M ÷ NA grams — one water molecule is 18 ÷ (6.022 × 10²³) ≈ 2.99 × 10⁻²³ g. (The full machinery of that bridge lives in § 1.8; using these masses in recipes is § 1.10.)

Isotope algebra runs in both directions, and JEE loves the reverse: given the average and both isotope masses, recover the abundances. Let the lighter isotope’s fraction be x: x·m₁ + (1 − x)·m₂ = x̄, so x = (m₂ − x̄)/(m₂ − m₁). Chlorine: x = (37 − 35.5)/(37 − 35) = 0.75 → 75% Cl-35, 25% Cl-37. One line, full marks — the lab below runs this live.

02

Visualising the u Scale

Ek standard, saare masses — the ¹²C pie defines the unit, the ruler places the elements, and the lab below averages isotopes like NTA asks.

The u scale: 1 u = 1/12 of one carbon-12 atom; element positions are relative masses, not gram weights FIG. 1 — THE u SCALE, ANCHORED TO CARBON-12 one slice = 1 u = 1.6605 × 10⁻²⁴ g ¹²C — the standard 1 u = 1/12 × m(one ¹²C atom) = 1.6605 × 10⁻²⁴ g · ¹²C = 12 u exact 0 10 20 30 40 50 60 70 u Hydrogen — 1 u H1 u Nitrogen — 14 u N14 u Sodium — 23 u Na23 u Chlorine — 35.5 u, an isotope average Cl35.5 u — average Copper — 63.5 u, an isotope average Cu63.5 u — average Carbon — 12 u, the anchor C12 u — anchor Sulfur — 32 u S32 u Oxygen — 16 u O16 u Iron — 56 u Fe56 u relative masses only — grams enter through 1 u or N_A
FIG. 1 — Every position on this ruler is a ratio against ¹²C, never a gram weight. Hydrogen sits near 1 u — one ¹²C atom balances twelve hydrogens. The red markers (Cl 35.5, Cu 63.5) are isotope averages: they land between whole numbers because nature ships mixtures, not because atoms are broken.
Try it live

Isotope Abundance Lab

Weighted average 35.50 u No single chlorine atom weighs 35.5 u — the average speaks for the mixture.

Reverse solve — the exam version

Average diya hai, abundance nahi — wahi NTA format. Algebra: x = (m₂ − x̄)/(m₂ − m₁) × 100, jahan x lighter isotope ka % hai.

Abundances follow exam convention (Cl 75 : 25, Ne 90.92 : 0.26 : 8.82 …). Sliders hold Σ = 100% automatically — the last isotope takes the remainder, exactly like the algebra.

03

Solved Examples (Step-by-Step)

Given → formula → substitute → verify. Write these same steps on your rough sheet — that is what earns full method marks.

EXAMPLE 01Foundation · NEET

Average atomic mass of chlorine

Chlorine occurs as Cl-35 (75%) and Cl-37 (25%). Using isotope masses 35 u and 37 u, calculate the atomic mass of chlorine. Compare with the periodic-table value.

  1. Givenm₁ = 35 u (f₁ = 0.75), m₂ = 37 u (f₂ = 0.25); f₁ + f₂ = 1 ✓
  2. Formulax̄ = f₁m₁ + f₂m₂
  3. Substitutex̄ = 0.75 × 35 + 0.25 × 37 = 26.25 + 9.25
  4. Verifyx̄ = 35.5 u — matches the table’s 35.45 (real masses 34.97/36.97 account for the gap).

x̄ = 35.5 u — an average no single atom carries

EXAMPLE 02JEE Main · Reverse algebra

From average back to abundance

Boron has two isotopes, B-10 (10 u) and B-11 (11 u), with an average atomic mass of 10.8 u. Find the percentage abundance of each isotope.

  1. Letx = fraction of B-10 → (1 − x) is B-11.
  2. Equation10x + 11(1 − x) = 10.8
  3. Solve11 − x = 10.8 → x = 0.2 — or one shot: x = (11 − 10.8)/(11 − 10) = 0.2
  4. Verify0.2 × 10 + 0.8 × 11 = 2 + 8.8 = 10.8 ✓

B-10 = 20% · B-11 = 80%

EXAMPLE 03JEE Main · Bridge to § 1.8

Molecular mass → mass of one glucose molecule

Calculate the molecular mass of glucose, C6H12O6, and the mass of a single glucose molecule in grams. (C = 12, H = 1, O = 16, NA = 6.022 × 10²³)

  1. SumM = 6(12) + 12(1) + 6(16) = 72 + 12 + 96
  2. Result (u)M = 180 u — the mass of one molecule on the relative scale.
  3. ConvertOne entity in grams: m = M/NA = 180 ÷ (6.022 × 10²³)
  4. Verifym ≈ 2.99 × 10⁻²² g — power of ten near 10⁻²², magnitude check passes ✓

M = 180 u · one molecule ≈ 2.99 × 10⁻²² g

05

Key Formulas & Takeaways

Formula card

Eight lines that solve this topic

1 u = 1/12 × m(¹²C) = 1.6605 × 10⁻²⁴ gThe unit itself — carbon-12 is the anchor at exactly 12 u.
x̄ = Σ (fᵢ × mᵢ)Average atomic mass; fᵢ = abundance fraction, Σfᵢ = 1.
% lighter = (m₂ − x̄)/(m₂ − m₁) × 100Reverse solve for a two-isotope system — the JEE favourite.
M(molecule) = Σ nᵢ × aᵢMolecular mass: sum atomic masses over the formula.
Ionic → formula mass, not molecularNaCl = 58.5 u per formula unit; terminology is graded.
m(one entity) = M / NASingle atom or molecule in grams — divide, never multiply.
1 u = 1/NA gWhy the relative scale and the gram scale agree.
M (g/mol) = M (u)Numerical bridge to molar mass — the § 1.8 handshake.

Anchors: ¹²C = 12 u exact  ·  1 u = 1.6605 × 10⁻²⁴ g  ·  NA = 6.022 × 10²³ mol⁻¹  ·  Cl avg = 35.5 u (75 : 25)  ·  Ne avg = 20.18 u  ·  H = 1, O = 16, C = 12 (exam convention)

  1. Atomic mass is a ratio, not a weight — ¹²C defines the scale; grams arrive only through 1 u or NA.
  2. Decimal atomic masses are isotope averages — 35.5 u belongs to the mixture; weighted mean, then reverse-solve when the average is given.
  3. Molecular vs formula mass is graded terminology — covalent molecules vs ionic lattices; the number can match, the word decides.
  4. One bridge line connects to § 1.8 — M u ↔ M g/mol ↔ M/NA g per entity; every numerical here flows through it.
06

FAQs

What is atomic mass and what is its unit?

Atomic mass is the mass of an atom measured relative to one-twelfth of a carbon-12 atom; its unit is the unified mass unit (u), where 1 u = 1.6605 × 10⁻²⁴ g. On this scale carbon-12 is exactly 12 u, hydrogen is about 1 u and chlorine averages 35.5 u.

Why is the atomic mass of chlorine 35.5 u?

Natural chlorine is a mixture of two isotopes — Cl-35 (about 75%) and Cl-37 (about 25%). The atomic mass is the weighted average: 0.75 × 35 + 0.25 × 37 = 35.5 u. No single chlorine atom actually weighs 35.5 u.

What is the difference between molecular mass and formula mass?

Molecular mass is the sum of atomic masses in one covalent molecule, e.g. H₂O = 18 u. Formula mass is used for ionic compounds like NaCl, which have no molecules — it is the sum for one formula unit, e.g. NaCl = 58.5 u. Both are numerically equal to the molar mass in g/mol.

How do you calculate the mass of one atom or one molecule?

Divide the molar mass by Avogadro’s constant: mass of one entity = M ÷ N_A grams. One oxygen atom: 16 ÷ (6.022 × 10²³) ≈ 2.66 × 10⁻²³ g; one water molecule: 18 ÷ (6.022 × 10²³) ≈ 2.99 × 10⁻²³ g.

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QCC Notes — Class 11 Chemistry

Strictly NCERT-aligned notes for JEE Main & NEET, prepared by QCC Notes (Padho Likho JEE). Content follows the latest NCERT edition and current NTA exam pattern.

Last updated
30 Aug 2026